The ratio of the density of oxygen nucleus (_ | vedclass

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(A) The density of a nucleus is given by the formula $\rho = \frac{M}{V}$, where $M$ is the mass of the nucleus and $V$ is its volume.The mass of a nu

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(A) The density of a nucleus is given by the formula $ho = \frac{M}{V}$, where $M$ is the mass of the nucleus and $V$ is its volume.The mass of a nucleus with mass number $A$ is approximately $M = A 	imes m_p$, where $m_p$ is the mass of a proton.The volume of a nucleus is given by $V = \frac{4}{3} \pi R^3$, where $R = R_0 A^{1/3}$ is the radius of the nucleus.Substituting the expression for $R$, we get $V = \frac{4}{3} \pi (R_0 A^{1/3})^3 = \frac{4}{3} \pi R_0^3 A$.Now, the density $ho = \frac{A 	imes m_p}{\frac{4}{3} \pi R_0^3 A} = \frac{3 m_p}{4 \pi R_0^3}$.Since the density $ho$ is independent of the mass number $A$, the density of all nuclei is constant.Therefore, the ratio of the density of oxygen nucleus to helium nucleus is $1 : 1$.

The ratio of the density of oxygen nucleus $(_{8}^{16}O)$ and helium nucleus $(_{2}^{4}He)$ is (in $: 1$)

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