The reaction conditions leading to the best y | vedclass

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(A) The free radical chlorination of alkanes is a chain reaction that often leads to a mixture of products due to polyhalogenation. To obtain the mono

Vedclass · Accepted Answer

$C_2H_6 	ext{ (excess)} + Cl_2 \xrightarrow{UV}$

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(A) The free radical chlorination of alkanes is a chain reaction that often leads to a mixture of products due to polyhalogenation. To obtain the mono-substituted product $C_2H_5Cl$ in the best yield,it is necessary to minimize further chlorination. By taking an excess of ethane $(C_2H_6)$,the probability of a chlorine radical colliding with an ethane molecule is significantly higher than its collision with a $C_2H_5Cl$ molecule. Therefore,$C_2H_6 	ext{ (excess)} + Cl_2 \xrightarrow{UV}$ is the condition that favors the formation of $C_2H_5Cl$ as the major product.

The reaction conditions leading to the best yields of $C_2H_5Cl$ are

Similar Questions

Given below are two statements $:$
Statement $(I) :$ Neopentane forms only one monosubstituted derivative.
Statement $(II) :$ Melting point of neopentane is higher than $n-$pentane.
In the light of the above statements,choose the most appropriate answer from the options given below $:$

Give the mechanism of chlorination of methane.

Compound $(P)$ is

One of the products formed in the following reaction is:
$C_6H_{11}MgBr + C_6H_{11}NH_2 \rightarrow ?$

Assertion $(A)$: Cyclohexane is the most stable cycloalkane.
Reason $(R)$: Cyclopropane and cyclobutane are less stable due to angle strain and torsional strain.
The correct answer is

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