The reaction of C_6H_5CH=CHCHO with LiAlH_4 g | vedclass

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Question

(A) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces both the aldehyde group $(-CHO)$ and the carbon-carbon double bond $

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$C_6H_5CH_2CH_2CH_2OH$

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(A) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces both the aldehyde group $(-CHO)$ and the carbon-carbon double bond $(C=C)$ when conjugated with an aromatic ring or an electron-withdrawing group. In the case of cinnamaldehyde $(C_6H_5CH=CHCHO)$,$LiAlH_4$ reduces both the aldehyde group to a primary alcohol and the double bond to a single bond,resulting in the formation of $3-phenylpropan-1-ol$ $(C_6H_5CH_2CH_2CH_2OH)$.

Reactant	$K_{eq.}$
$PhCHO$	$a$
$CH_3CH_2COCH_3$	$b$
$PhCOCH_3$	$c$
$CH_3CHO$	$d$

The reaction of $C_6H_5CH=CHCHO$ with $LiAlH_4$ gives

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