The reagent 'R' in the given sequence of chem | vedclass

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Question

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$

Vedclass · Accepted Answer

$CH_{3}CH_{2}OH$

Vedclass · Answer

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$ at $0-5^{\circ}C$. To replace the diazonium group $(-N_{2}^{+}Cl^{-})$ with a hydrogen atom,a reducing agent is required. Ethanol $(CH_{3}CH_{2}OH)$ acts as a mild reducing agent that reduces the diazonium salt to the corresponding aromatic hydrocarbon (in this case,$1,3,5$-tribromobenzene) while being oxidized to acetaldehyde. Therefore,the reagent '$R$' is $CH_{3}CH_{2}OH$.

The reagent '$R$' in the given sequence of chemical reaction is:

Similar Questions

The incorrect statement regarding the reaction given below is:

The major product $B$ in the following reaction sequence is:
$CH_3-CH_2-CH(CH_3)-CONH_2$ $\xrightarrow{Br_2/KOH, \Delta} (A)$ $\xrightarrow{(1) CH_3I (excess), (2) AgOH/\Delta} (B)$

Mark the correct statement.

How many secondary amines are possible with the molecular formula $C_4H_{11}N$?

Identify the major product $(G)$ in the following reaction:

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