The resistivity of a potentiometer wire is $40 \times 10^{-8} \Omega \text{ m}$ and its area of cross-section is $8 \times 10^{-6} \text{ m}^2$. If $0.2 \text{ A}$ current is flowing through the wire, the potential gradient of the wire is:

  • A
    $0.1 \text{ V m}^{-1}$
  • B
    $10^{-2} \text{ V m}^{-1}$
  • C
    $10^{-3} \text{ V m}^{-1}$
  • D
    $10^{-4} \text{ V m}^{-1}$

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