The runs scored by two teams $A$ and $B$ on the first $60$ balls in a cricket match are given below:

Number of balls	Teams $A$	Teams $B$
$1-6$	$2$	$5$
$7-12$	$1$	$6$
$13-18$	$8$	$2$
$19-24$	$9$	$10$
$25-30$	$4$	$5$
$31-36$	$5$	$6$
$37-42$	$6$	$3$
$43-48$	$10$	$4$
$49-54$	$6$	$8$
$55-60$	$2$	$10$

Represent the data of both the teams on the same graph by frequency polygons.
[Hint : First make the class intervals continuous.]

(N/A) It can be observed that the class intervals of the given data are not continuous.
There is a gap of $1$ in between them. Therefore,$1/2 = 0.5$ has to be added to the upper class limits and $0.5$ has to be subtracted from the lower class limits.
Also,the class mark of each interval can be found by using the following formula:
Class mark $= \frac{\text{Upper class limit} + \text{Lower class limit}}{2}$
Continuous data with the class mark of each class interval can be represented as follows:

Number of balls	Class mark	Team $A$	Team $B$
$0.5-6.5$	$3.5$	$2$	$5$
$6.5-12.5$	$9.5$	$1$	$6$
$12.5-18.5$	$15.5$	$8$	$2$
$18.5-24.5$	$21.5$	$9$	$10$
$24.5-30.5$	$27.5$	$4$	$5$
$30.5-36.5$	$33.5$	$5$	$6$
$36.5-42.5$	$39.5$	$6$	$3$
$42.5-48.5$	$45.5$	$10$	$4$
$48.5-54.5$	$51.5$	$6$	$8$
$54.5-60.5$	$57.5$	$2$	$10$

By taking class marks on the $x$-axis and runs scored on the $y$-axis,a frequency polygon can be constructed as shown in the graph.