The size of the species Pb,Pb^{2+},and Pb^{4+ | vedclass

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Question

(B) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For a given element,the neutral atom $(Pb)$ has th

Vedclass · Accepted Answer

$Pb > Pb^{2+} > Pb^{4+}$

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(B) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For a given element,the neutral atom $(Pb)$ has the largest size because it has the most electrons and the least effective nuclear charge per electron. When electrons are removed to form cations ($Pb^{2+}$ and $Pb^{4+}$),the remaining electrons experience a greater effective nuclear charge,causing the electron cloud to be pulled closer to the nucleus. Therefore,as the positive charge on the ion increases,the ionic radius decreases. Thus,the order of size is $Pb > Pb^{2+} > Pb^{4+}$.

$A$. Element	$B$. Atomic Radius $(pm)$
$A$. $Be$	$I$. $74$
$B$. $C$	$II$. $77$
$C$. $O$	$III$. $66$
$D$. $B$	$IV$. $88$
$E$. $N$	$V$. $111$

The size of the species $Pb$,$Pb^{2+}$,and $Pb^{4+}$ decreases as:

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$A$. Element $B$. Atomic Radius $(pm)$

$A$. $Be$ $I$. $74$

$B$. $C$ $II$. $77$

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