The solution set of x-y geq 0 is shown graphi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given inequality is $x - y \geq 0$,which can be rewritten as $x \geq y$ or $y \leq x$. To graph this,we first consider the boundary line $x -

Vedclass · Accepted Answer

Vedclass · Answer

(C) The given inequality is $x - y \geq 0$,which can be rewritten as $x \geq y$ or $y \leq x$. To graph this,we first consider the boundary line $x - y = 0$,which is the line $y = x$. Since the inequality is $\geq$ (greater than or equal to),the boundary line $y = x$ must be included in the solution set,so we draw it as a solid line. Next,we test a point not on the line,such as $(1, 0)$. Substituting $(1, 0)$ into the inequality: $1 - 0 = 1$,and $1 \geq 0$ is true. Therefore,the region containing the point $(1, 0)$ is the solution set. This corresponds to the region below the line $y = x$ (where $x$ values are greater than $y$ values). Looking at the options,the graph in Option $C$ shows the solid line $x - y = 0$ with the shaded region below it.

The solution set of $x-y \geq 0$ is shown graphically by

Similar Questions

Solve the following inequality graphically in a two-dimensional plane: $2x + y > 3$.

The shaded region given in the figure represents the $\ldots \ldots \ldots$ inequality.

Solve the given inequality for real $x: 3(2-x) \geq 2(1-x)$

Solve the given inequality graphically in a two-dimensional plane: $x > -3$

Solve $-12x > 30,$ when $x$ is an integer.

Vedclass Test Series

Exam Paper Generator

Online Exam Module