The solution set of the pair of equations x+y | vedclass

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(B) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinitely many solutions,the condition is $\frac{a_1}{

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$3$

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(B) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinitely many solutions,the condition is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$.Given equations are $x + y + 1 = 0$ and $3x + 3y + k = 0$.Here,$a_1 = 1, b_1 = 1, c_1 = 1$ and $a_2 = 3, b_2 = 3, c_2 = k$.Applying the condition: $\frac{1}{3} = \frac{1}{3} = \frac{1}{k}$.Therefore,$\frac{1}{3} = \frac{1}{k}$,which implies $k = 3$.

The solution set of the pair of equations $x+y+1=0$ and $3x+3y+k=0$ is an infinite set. Then $k = \dots$

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