The speed-time graph for a body moving along | vedclass

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(D) The average acceleration is defined as the total change in velocity divided by the total time interval.From the graph,the initial velocity at $t =

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All of these

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(D) The average acceleration is defined as the total change in velocity divided by the total time interval.From the graph,the initial velocity at $t = 0 \, s$ is $v_i = 20 \, m/s$.The final velocity at $t = 10 \, s$ is $v_f = 20 \, m/s$.The average acceleration $a_{avg} = \frac{v_f - v_i}{t_f - t_i} = \frac{20 - 20}{10 - 0} = 0 \, m/s^2$.However,the question asks for the acceleration that the body *may* have,implying we should consider different intervals:$1$. For the interval $t = 0$ to $5 \, s$: $a = \frac{0 - 20}{5 - 0} = -4 \, m/s^2$.$2$. For the interval $t = 5$ to $10 \, s$: $a = \frac{20 - 0}{10 - 5} = 4 \, m/s^2$.$3$. For the total interval $t = 0$ to $10 \, s$: $a_{avg} = 0 \, m/s^2$.Since all these values are possible accelerations for different segments or the whole motion,the correct option is $(d)$.

The speed-time graph for a body moving along a straight line is shown in the figure. The average acceleration of the body may be .......... $m/s^2$.

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