The statement (p wedge (sim q)) Rightarrow (p | vedclass

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(B) Let the given statement be $S = (p \wedge \sim q)$ $\Rightarrow (p$ $\Rightarrow \sim q)$.Using the implication law $A \Rightarrow B \equiv \sim A

Vedclass · Accepted Answer

a tautology

Vedclass · Answer

(B) Let the given statement be $S = (p \wedge \sim q)$ $\Rightarrow (p$ $\Rightarrow \sim q)$.Using the implication law $A \Rightarrow B \equiv \sim A \vee B$,we get:$S \equiv \sim (p \wedge \sim q) \vee (p \Rightarrow \sim q)$$S \equiv (\sim p \vee \sim (\sim q)) \vee (\sim p \vee \sim q)$$S \equiv (\sim p \vee q) \vee (\sim p \vee \sim q)$Using the associative and commutative laws:$S \equiv \sim p \vee (q \vee \sim q)$Since $(q \vee \sim q)$ is a tautology $(t)$:$S \equiv \sim p \vee t$$S \equiv t$Therefore,the statement is a tautology.

The statement $(p \wedge (\sim q))$ $\Rightarrow (p$ $\Rightarrow (\sim q))$ is

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