The sum of the series 5.05 + 1.212 + 0.29088 | vedclass

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(D) The given series is $5.05 + 1.212 + 0.29088 + ... \infty$.This is an infinite geometric progression $(G.P.)$ where the first term $a = 5.05$.The c

Vedclass · Accepted Answer

$6.64474$

Vedclass · Answer

(D) The given series is $5.05 + 1.212 + 0.29088 + ... \infty$.This is an infinite geometric progression $(G.P.)$ where the first term $a = 5.05$.The common ratio $r$ is calculated as $r = \frac{1.212}{5.05} = 0.24$.Since $|r| Substituting the values,we get $S_{\infty} = \frac{5.05}{1 - 0.24} = \frac{5.05}{0.76}$.Calculating the division,$S_{\infty} = 6.6447368... \approx 6.64474$.

The sum of the series $5.05 + 1.212 + 0.29088 + ... \infty$ is

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