The surface area of a spherical ball is increasing at the rate of $4\pi \text{ cm}^2/\text{s}$. The rate at which the radius is increasing when the surface area is $16\pi \text{ cm}^2$ is (in $\text{ cm/s}$)

  • A
    $0.5$
  • B
    $0.25$
  • C
    $0.125$
  • D
    $1$

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