The synthesis of crotonaldehyde from acetalde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The synthesis of crotonaldehyde from acetaldehyde occurs in two steps: $1$. Aldol condensation of two molecules of acetaldehyde $(CH_3CHO)$ in the

Vedclass · Accepted Answer

nucleophilic addition-elimination

Vedclass · Answer

(D) The synthesis of crotonaldehyde from acetaldehyde occurs in two steps: $1$. Aldol condensation of two molecules of acetaldehyde $(CH_3CHO)$ in the presence of dilute $NaOH$ to form $3-$hydroxybutanal (aldol). This step is a nucleophilic addition reaction. $2$. Dehydration (elimination of water) of $3-$hydroxybutanal upon heating to form crotonaldehyde $(CH_3CH=CHCHO)$. Since the overall process involves both nucleophilic addition and elimination,it is classified as a nucleophilic addition-elimination reaction.

The synthesis of crotonaldehyde from acetaldehyde is an example of ....... reaction.

Similar Questions

Write a test to differentiate between pentan$-2-$one and pentan$-3-$one.

Identify the products $A$,$B$,and $C$ in the following reaction sequence:
$C_6H_5CONH_2$ $\xrightarrow{P_2O_5, \Delta} A$ $\xrightarrow[(ii) H_2O]{(i) DIBAL-H} B$
$A \xrightarrow[(ii) H_3O^+, \Delta]{(i) (CH_3CO)_2O/CH_3COONa} C$

Which of the following does not give a yellow precipitate with $I_2$ and $NaOH$?

Identify the main product of the following reaction: $R - CO - O - R' \xrightarrow[H_3O^+]{DIBAL-H} \text{Product}$

$C_2H_5CHO$ and $(CH_3)_2CO$ can be distinguished by testing with

Vedclass Test Series

Exam Paper Generator

Online Exam Module