(D) Given the equation: $y^3-4x^2y=0$ Factorizing the equation: $y(y^2-4x^2)=0$ Using the identity $a^2-b^2=(a-b)(a+b)$,we get: $y(y-2x)(y+2x)=0$ This

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(D) Given the equation: $y^3-4x^2y=0$ Factorizing the equation: $y(y^2-4x^2)=0$ Using the identity $a^2-b^2=(a-b)(a+b)$,we get: $y(y-2x)(y+2x)=0$ This gives the three lines: $L_1: y=0$,$L_2: y=2x$,and $L_3: y=-2x$. All three lines pass through the origin $(0,0)$. Since all three lines intersect at a single common point $(0,0)$,they are concurrent lines.

Class 11 Mathematics Pair of straight lines Bisectors of the angle between the lines, Point of intersection of the lines

Medium

The three lines given by the combined equation $y^3-4x^2y=0$ represent:

AP EAMCET 2021 All AP EAMCET

A
the sides of an isosceles triangle
B
the sides of a right-angled triangle
C
the sides of an equilateral triangle
D
concurrent lines

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Class 11

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Pair of straight lines

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Bisectors of the angle between the lines, Point of intersection of the lines

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DifficultAIEEE 2007

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The point of intersection of the lines represented by the equation $2x^2 + 7xy + 3y^2 + 8x + 14y + 8 = 0$ is

Medium

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The equation of the straight line passing through the point of intersection of the lines represented by $x^2+4xy+3y^2-4x-10y+3=0$ and the point $(2,2)$ is

MediumAP EAMCET 2024

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The three lines given by the combined equation $y^3-4x^2y=0$ represent:

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If the bisectors of the angles between the pairs of lines given by the equations $ax^2 + 2hxy + by^2 = 0$ and $ax^2 + 2hxy + by^2 + \lambda(x^2 + y^2) = 0$ are coincident,then $\lambda = $

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