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(A) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the length of the pendulum and $g$ is

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(A) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the length of the pendulum and $g$ is the acceleration due to gravity.On the surface of the moon,the acceleration due to gravity $g_m$ is approximately $1/6$th of the acceleration due to gravity on Earth $(g_e)$.Since $T \propto \frac{1}{\sqrt{g}}$,a decrease in the value of $g$ leads to an increase in the time period $T$.Therefore,the time period of a simple pendulum increases when it oscillates on the surface of the moon.

The time period of a simple pendulum when it is made to oscillate on the surface of the moon:

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