The torque on a bar magnet due to the earth's | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin \

Vedclass · Accepted Answer

Perpendicular to the field of the earth

Vedclass · Answer

(A) The torque $	au$ acting on a bar magnet of magnetic moment $M$ placed in an external magnetic field $B$ is given by the formula $	au = MB \sin 	heta$,where $	heta$ is the angle between the magnetic axis and the magnetic field.For the earth's magnetic field,the torque is $	au = M B_H \sin 	heta$,where $B_H$ is the horizontal component of the earth's magnetic field.The torque $	au$ is maximum when $\sin 	heta$ is maximum,which occurs at $	heta = 90^{\circ}$.Therefore,the torque is maximum when the axis of the magnet is perpendicular to the earth's magnetic field.

The torque on a bar magnet due to the earth's magnetic field is maximum when the axis of the magnet is

Similar Questions

$A$ bar magnet having pole strength $q_m$ and magnetic moment $m$ is divided into two equal parts along its length. The new pole strength is . . . . . . and the magnetic moment is . . . . . . respectively.

Give some of the commonly known ideas regarding magnetism.

What is the magnetism analog of charge in electricity?

If a hole is made at the centre of a bar magnet,then its magnetic moment will

The magnetic moment of a magnet of length $10\, cm$ and pole strength $4.0\, Am$ will be......$A\,m^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module