The total number of optically active compound | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of the given vinyl ether with $HBr$ involves the protonation of the double bond followed by the nucleophilic attack of $Br^-$ to form

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) The reaction of the given vinyl ether with $HBr$ involves the protonation of the double bond followed by the nucleophilic attack of $Br^-$ to form a bromo-ether product.The product formed has two chiral centers.For a molecule with $n$ chiral centers,the maximum number of stereoisomers is $2^n$.Here,$n = 2$,so there are $2^2 = 4$ stereoisomers.Since all four stereoisomers are chiral (optically active),the total number of optically active compounds formed is $4$.

The total number of optically active compounds formed in the following reaction is
$CH_3CH_2C(CH_3)=CHOCH(CH_3)_2$ $\xrightarrow{HBr}$

Similar Questions

The reaction of $C_6H_5CH=CHCH_3$ with $HBr$ produces

Which of the following alkyl halides has the highest boiling point?

Which is most reactive for $SN^2$ reaction?

In the alkaline hydrolysis of a tertiary alkyl halide by aqueous alkali,if the concentration of the alkali is doubled,then the reaction rate:

$CH_3Br + Nu^{-} \rightarrow CH_3-Nu + Br^{-}$
The decreasing order of the rate of the above reaction with nucleophiles $(Nu^{-})$ $A$ to $D$ is
$[Nu^{-} = (A) \, PhO^{-}, (B) \, AcO^{-}, (C) \, HO^{-}, (D) \, CH_3O^{-}]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The total number of optically active compounds formed in the following reaction is$CH_3CH_2C(CH_3)=CHOCH(CH_3)_2$ $\xrightarrow{HBr}$