The unit vector in the direction of the vecto | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $\vec{a} = (2, 2, -1)$.The magnitude of the vector $\vec{a}$ is given by $|\vec{a}| = \sqrt{2^2 + 2^2 + (-1)^2} = \sqrt{4 + 4 + 1} = \sqrt{9}

Vedclass · Accepted Answer

$\left(\frac{2}{3}, \frac{2}{3}, \frac{-1}{3}\right)$

Vedclass · Answer

(A) Let $\vec{a} = (2, 2, -1)$.The magnitude of the vector $\vec{a}$ is given by $|\vec{a}| = \sqrt{2^2 + 2^2 + (-1)^2} = \sqrt{4 + 4 + 1} = \sqrt{9} = 3$.The unit vector in the direction of $\vec{a}$ is denoted by $\hat{a}$ and is calculated as $\hat{a} = \frac{\vec{a}}{|\vec{a}|}$.Substituting the values,we get $\hat{a} = \frac{1}{3}(2, 2, -1) = \left(\frac{2}{3}, \frac{2}{3}, \frac{-1}{3}\right)$.

The unit vector in the direction of the vector $\vec{a} = (2, 2, -1)$ is $......$

Similar Questions

In the given figure (a square),identify the co-initial vectors.

Let $\alpha, \beta, \gamma$ be distinct real numbers. The points with position vectors $\alpha \hat{i} + \beta \hat{j} + \gamma \hat{k}$,$\beta \hat{i} + \gamma \hat{j} + \alpha \hat{k}$,and $\gamma \hat{i} + \alpha \hat{j} + \beta \hat{k}$ form:

If $|\bar{a}|=3, |\bar{b}|=4, |\bar{a}-\bar{b}|=5$,then $|\bar{a}+\bar{b}|=$

If $C$ is the mid-point of line segment $AB$ and $P$ is any point not on the line $AB$,then

If $a = 2i + 2j - k$ and $|xa| = 1$,then $x =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module