sqrt{3} , text{cosec} , 20^circ - text{sec} , | vedclass

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(C) ધારો કે $E = \sqrt{3} \, 	ext{cosec} \, 20^\circ - 	ext{sec} \, 20^\circ = \frac{\sqrt{3}}{\sin 20^\circ} - \frac{1}{\cos 20^\circ}$ $E = \frac{

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) ધારો કે $E = \sqrt{3} \, 	ext{cosec} \, 20^\circ - 	ext{sec} \, 20^\circ = \frac{\sqrt{3}}{\sin 20^\circ} - \frac{1}{\cos 20^\circ}$ $E = \frac{\sqrt{3} \cos 20^\circ - \sin 20^\circ}{\sin 20^\circ \cos 20^\circ}$ અંશ અને છેદને $2$ વડે ગુણતા: $E = \frac{2(\frac{\sqrt{3}}{2} \cos 20^\circ - \frac{1}{2} \sin 20^\circ)}{\frac{1}{2} (2 \sin 20^\circ \cos 20^\circ)}$ $E = \frac{4(\sin 60^\circ \cos 20^\circ - \cos 60^\circ \sin 20^\circ)}{\sin 40^\circ}$ $E = \frac{4 \sin(60^\circ - 20^\circ)}{\sin 40^\circ} = \frac{4 \sin 40^\circ}{\sin 40^\circ} = 4$

$\sqrt{3} \, \text{cosec} \, 20^\circ - \text{sec} \, 20^\circ$ ની કિંમત શું છે?

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$\cos ^4 \frac{\pi}{8}+\cos ^4 \frac{2 \pi}{8}+\cos ^4 \frac{3 \pi}{8}+\cos ^4 \frac{4 \pi}{8}+\cos ^4 \frac{5 \pi}{8}+\cos ^4 \frac{6 \pi}{8}+\cos ^4 \frac{7 \pi}{8}+\cos ^4 \frac{8 \pi}{8}$ ની કિંમત શોધો.

જો $\frac{\sin ^4 x}{2}+\frac{\cos ^4 x}{3}=\frac{1}{5}$ હોય,તો
$(A) \tan ^2 x=\frac{2}{3}$ $(B) \frac{\sin ^8 x}{8}+\frac{\cos ^8 x}{27}=\frac{1}{125}$
$(C) \tan ^2 x=\frac{1}{3}$ $(D) \frac{\sin ^8 x}{8}+\frac{\cos ^8 x}{27}=\frac{2}{125}$

જો $\sin (\theta + \alpha ) = a$ અને $\sin (\theta + \beta ) = b$ હોય,તો $\cos 2(\alpha - \beta ) - 4ab\cos (\alpha - \beta )$ ની કિંમત શોધો.

જો $\tan (\pi \cos \theta ) = \cot (\pi \sin \theta )$ હોય,તો $\cos \left( \theta - \frac{\pi }{4} \right)$ ની કિંમત શોધો.

$\frac{\cos 15^{\circ} \cos^2 22\frac{1}{2}^{\circ} - \sin 75^{\circ} \sin^2 52\frac{1}{2}^{\circ}}{\cos^2 15^{\circ} - \cos^2 75^{\circ}} = $

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