left(sin 70^{circ}right)left(cot 10^{circ} co | vedclass

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(A) ધારો કે $E = \sin 70^{\circ} (\cot 10^{\circ} \cot 70^{\circ} - 1)$.$\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$ નો ઉપયોગ કરતા:$E = \sin 70^{\c

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$1$

Vedclass · Answer

(A) ધારો કે $E = \sin 70^{\circ} (\cot 10^{\circ} \cot 70^{\circ} - 1)$.$\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$ નો ઉપયોગ કરતા:$E = \sin 70^{\circ} \left( \frac{\cos 10^{\circ} \cos 70^{\circ}}{\sin 10^{\circ} \sin 70^{\circ}} - 1 ight)$$E = \sin 70^{\circ} \left( \frac{\cos 10^{\circ} \cos 70^{\circ} - \sin 10^{\circ} \sin 70^{\circ}}{\sin 10^{\circ} \sin 70^{\circ}} ight)$$\cos(A+B) = \cos A \cos B - \sin A \sin B$ નિત્યસમનો ઉપયોગ કરતા:$E = \sin 70^{\circ} \left( \frac{\cos(10^{\circ} + 70^{\circ})}{\sin 10^{\circ} \sin 70^{\circ}} ight)$$E = \sin 70^{\circ} \left( \frac{\cos 80^{\circ}}{\sin 10^{\circ} \sin 70^{\circ}} ight)$$\cos 80^{\circ} = \sin(90^{\circ} - 80^{\circ}) = \sin 10^{\circ}$ હોવાથી:$E = \sin 70^{\circ} \left( \frac{\sin 10^{\circ}}{\sin 10^{\circ} \sin 70^{\circ}} ight) = 1$.

$\left(\sin 70^{\circ}\right)\left(\cot 10^{\circ} \cot 70^{\circ}-1\right)$ નું મૂલ્ય શું છે?

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