The variation of solubility of four different | vedclass

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(D) According to Henry's law,$p = K_H \chi$,where $K_H$ is Henry's constant and $\chi$ is the mole fraction (solubility). Rearranging the equation,we

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$G_1$

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(D) According to Henry's law,$p = K_H \chi$,where $K_H$ is Henry's constant and $\chi$ is the mole fraction (solubility). Rearranging the equation,we get $\chi = \frac{p}{K_H}$. This implies that for a given pressure $p$,the solubility $\chi$ is inversely proportional to the Henry's law constant $K_H$. Therefore,the gas with the lowest solubility at a given pressure will have the highest value of $K_H$. Based on the typical plot where $G_1$ shows the least slope (lowest solubility),$G_1$ has the highest value of Henry's law constant.

The variation of solubility of four different gases $(G_1, G_2, G_3, G_4)$ in a given solvent with pressure at a constant temperature is shown in the plot. The gas with the highest value of Henry's law constant is

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