The velocity-time graph for a particle moving along the $x$-axis is shown in the figure. The corresponding displacement-time graph is correctly shown by

If $t = \sqrt{x} + 4$,then $\left(\frac{dx}{dt}\right)_{t=4}$ is:

The graph of an object's motion (along the $x-$ axis) is shown in the figure. The instantaneous velocity of the object at points $A$ and $B$ are $v_A$ and $v_B$ respectively. Then

From the velocity-time graph of a particle moving in a straight line,decide which of the following is an incorrect statement.

Two small blocks slide without losing contact with the surface along two frictionless tracks $1$ and $2$,starting at the same time with the same initial speed $v$. Track $1$ is perfectly horizontal,while track $2$ has a dip in the middle,as shown in the figure. Which block reaches the finish line first? [Hint: Use velocity-time graph to solve]

Which of the following options is correct for the object having a straight-line motion represented by the following graph?