The vertices of Delta ABC are A(3, 4),B(0, 0) | vedclass

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(C) The median $\overline{AD}$ connects vertex $A$ to the midpoint $D$ of the opposite side $\overline{BC}$.Since $B = (0, 0)$ and $C = (6, 0)$,the co

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$4$

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(C) The median $\overline{AD}$ connects vertex $A$ to the midpoint $D$ of the opposite side $\overline{BC}$.Since $B = (0, 0)$ and $C = (6, 0)$,the coordinates of the midpoint $D$ are calculated using the midpoint formula:$D = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{0 + 6}{2}, \frac{0 + 0}{2} \right) = (3, 0)$.Now,we find the length of the segment $\overline{AD}$ between $A(3, 4)$ and $D(3, 0)$ using the distance formula:$AD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(3 - 3)^2 + (0 - 4)^2} = \sqrt{0^2 + (-4)^2} = \sqrt{16} = 4$.Therefore,the length of the median $\overline{AD}$ is $4$.

The vertices of $\Delta ABC$ are $A(3, 4)$,$B(0, 0)$,and $C(6, 0)$. Then the length of the median $\overline{AD}$ is:

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