The water rises in the capillary to a height of $10\, cm$. If the surface tension of water is $73 \times 10^{-3}\, N/m$,density is $10^3\, kg/m^3$ and $g = 9.8\, m/s^2$,then find the radius of the capillary. (in $, cm$)

Two capillary tubes of different diameters are dipped in water. The rise of water is

Water rises to a height of $15 \,mm$ in a capillary tube having cross-sectional area $A$. If the cross-sectional area of the tube is made $A / 3$, then the water will rise to a height of:

Liquid $A$ rises to a height of $10 \ cm$ in a capillary tube and liquid $B$ falls to a depth of $2 \ cm$ in the same tube. The densities of $A$ and $B$ are $1 \ g/cm^3$ and $10 \ g/cm^3$ respectively. The contact angles of $A$ and $B$ with the tube are $0^{\circ}$ and $135^{\circ}$ respectively. If the surface tensions of $A$ and $B$ are $S_A$ and $S_B$, then the ratio $\frac{S_B}{S_A}$ is:

In a capillary tube experiment, a vertical $30 \text{ cm}$ long capillary tube is dipped in water. Water rises up to a height of $10 \text{ cm}$ due to capillarity. If this experiment is conducted in a freely falling elevator, then the length of the water column becomes

$A$ capillary tube of radius $R$ is dipped in water,and water rises to a height $H$. The mass of water in the capillary tube is $M$. If a capillary tube of half the radius is dipped in water,what will be the mass of the water in the capillary tube?