Water rises to a height of $15 \,mm$ in a capillary tube having cross-sectional area $A$. If the cross-sectional area of the tube is made $A / 3$, then the water will rise to a height of:

  • A
    $15 \sqrt{3} \times 10^{-3} \,m$
  • B
    $20 \sqrt{3} \times 10^{-3} \,m$
  • C
    $5 \sqrt{3} \times 10^{-3} \,m$
  • D
    $10 \sqrt{3} \times 10^{-3} \,m$

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