The work done by a gas is maximum when it exp | vedclass

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(C) The work done by a gas during expansion is given by the area under the $P-V$ curve,$W = \int_{V_1}^{V_2} P \, dV$. For a given change in volume fr

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Isobaric expansion

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(C) The work done by a gas during expansion is given by the area under the $P-V$ curve,$W = \int_{V_1}^{V_2} P \, dV$. For a given change in volume from $V_1$ to $V_2$,the pressure $P$ must be as high as possible throughout the process to maximize the integral. In an isobaric process,the pressure remains constant at its initial maximum value. In other processes like isothermal or adiabatic,the pressure decreases as the volume increases. Therefore,the area under the $P-V$ curve is largest for an isobaric expansion,making the work done maximum.

The work done by a gas is maximum when it expands from a volume $V_1$ to $V_2$. This expansion is:

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