The zeros of p(x) = x^{3} - 4x are .......... | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the zeros of the polynomial $p(x) = x^{3} - 4x$,we set $p(x) = 0$.$x^{3} - 4x = 0$Factor out $x$ from the expression:$x(x^{2} - 4) = 0$Usi

Vedclass · Accepted Answer

$0, \pm 2$

Vedclass · Answer

(D) To find the zeros of the polynomial $p(x) = x^{3} - 4x$,we set $p(x) = 0$.$x^{3} - 4x = 0$Factor out $x$ from the expression:$x(x^{2} - 4) = 0$Using the difference of squares formula $a^{2} - b^{2} = (a - b)(a + b)$,we can write $x^{2} - 4$ as $(x - 2)(x + 2)$:$x(x - 2)(x + 2) = 0$Setting each factor to zero,we get:$x = 0$,$x - 2 = 0 \Rightarrow x = 2$,and $x + 2 = 0 \Rightarrow x = -2$.Thus,the zeros are $0, 2, -2$,which can be written as $0, \pm 2$.

The zeros of $p(x) = x^{3} - 4x$ are .............

Similar Questions

Find the zeros of the following quadratic polynomial: $15x^2 + 16x + 4$.

The number of real zeros of $y=p(x)$ is ........... in the given figure.

The coefficient of the underlined term of $p(x) = 7 - \underline{5x^4} - 2x^3 - x^2$ is $\ldots \ldots$

State the degree of the following polynomial: $p(x) = (x^{1/2})^{50} - 5x^{10} - 9x^2 + 15$.

The graph of $\ldots \ldots \ldots$ is a curve open upwards.

Vedclass Test Series

Exam Paper Generator

Online Exam Module