The zeros of the cubic polynomial p(x) = ax^3 | vedclass

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(C) For a cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$,the relationship between the zeros and the coefficients is given by Vieta's formulas.Let the

Vedclass · Accepted Answer

$-\frac{b}{a}$

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(C) For a cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$,the relationship between the zeros and the coefficients is given by Vieta's formulas.Let the zeros be $\alpha, \beta$,and $\gamma$.The sum of the zeros is given by the formula:$\alpha + \beta + \gamma = -\frac{	ext{coefficient of } x^2}{	ext{coefficient of } x^3}$Substituting the coefficients from the given polynomial:$\alpha + \beta + \gamma = -\frac{b}{a}$Therefore,the correct option is $C$.

The zeros of the cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$; where $a \neq 0$ and $a, b, c, d \in R$,are $\alpha, \beta$,and $\gamma$. Then $\alpha + \beta + \gamma = \ldots$

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