Three charges q, sqrt{2}q,and 2q are placed a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electric potential $V$ at a point due to a system of point charges is the algebraic sum of the potentials due to each charge individually: $V

Vedclass · Accepted Answer

$\frac{4kq}{a}$

Vedclass · Answer

(B) The electric potential $V$ at a point due to a system of point charges is the algebraic sum of the potentials due to each charge individually: $V = \sum \frac{kq_i}{r_i}$.In square $ABCD$ of side $a$:$1$. The distance from $A$ to $D$ is $r_A = a$.$2$. The distance from $B$ to $D$ is the diagonal of the square,$r_B = a\sqrt{2}$.$3$. The distance from $C$ to $D$ is $r_C = a$.The potential at $D$ is $V_D = \frac{kq_A}{r_A} + \frac{kq_B}{r_B} + \frac{kq_C}{r_C}$.Substituting the values: $V_D = \frac{kq}{a} + \frac{k(\sqrt{2}q)}{a\sqrt{2}} + \frac{k(2q)}{a}$.$V_D = \frac{kq}{a} + \frac{kq}{a} + \frac{2kq}{a} = \frac{kq}{a}(1 + 1 + 2) = \frac{4kq}{a}$.

Three charges $q, \sqrt{2}q$,and $2q$ are placed at the corners $A, B$,and $C$ respectively of a square $ABCD$ of side length $a$. Find the electric potential at point $D$.

Similar Questions

Two points $P$ and $Q$ are at potentials of $10 \ V$ and $-4 \ V$ respectively. The work done in moving $100$ electrons from $P$ to $Q$ is .....

The potential at a point,due to a positive charge of $100\,\mu C$ at a distance of $9\,m$,is

Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively,which are a distance $2L$ apart. $C$ is the midpoint between $A$ and $B$. The work done in moving a charge $+Q$ along the semicircle $CRD$ is

If a unit positive charge is shifted from a region of low potential to a region of high potential,then the electric potential energy of the system

Calculate the electric potential on the axis of a disc of radius $R$ due to a charge $Q$ uniformly distributed on its surface.

Vedclass Test Series

Exam Paper Generator

Online Exam Module