Three times the present age of a father is eq | vedclass

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(B) Let the present age of the father be $F$ and the present age of the son be $S$.According to the first condition: $3F = 8S$,which implies $F = \fra

Vedclass · Accepted Answer

$32, 12$

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(B) Let the present age of the father be $F$ and the present age of the son be $S$.According to the first condition: $3F = 8S$,which implies $F = \frac{8}{3}S$.According to the second condition,after $8$ years: $(F + 8) = 2(S + 8)$.Substitute $F = \frac{8}{3}S$ into the second equation:$\frac{8}{3}S + 8 = 2(S + 8)$$\frac{8}{3}S + 8 = 2S + 16$Multiply the entire equation by $3$ to clear the fraction:$8S + 24 = 6S + 48$$8S - 6S = 48 - 24$$2S = 24$$S = 12$.Now,find the father's age $F$:$F = \frac{8}{3} 	imes 12 = 8 	imes 4 = 32$.Thus,the present age of the father is $32$ years and the son is $12$ years.

Three times the present age of a father is equal to eight times the present age of his son. $8$ years hence,the father will be twice as old as his son at that time. What are their present ages?

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