To generate a power of 3.2 text{ MW},the numb | vedclass

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(A) Given: Power $P = 3.2 	ext{ MW} = 3.2 	imes 10^6 	ext{ J/s}$.Energy released per fission $E = 200 	ext{ MeV} = 200 	imes 10^6 	imes 1.6 	im

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$6 	imes 10^{18}$

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(A) Given: Power $P = 3.2 	ext{ MW} = 3.2 	imes 10^6 	ext{ J/s}$.Energy released per fission $E = 200 	ext{ MeV} = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.Number of fissions per second $n = \frac{P}{E} = \frac{3.2 	imes 10^6}{3.2 	imes 10^{-11}} = 10^{17} 	ext{ fissions/s}$.Number of fissions per minute $= n 	imes 60 = 10^{17} 	imes 60 = 6 	imes 10^{18} 	ext{ fissions/min}$.

To generate a power of $3.2 \text{ MW}$,the number of fissions of $^{235}\text{U}$ per minute is (Energy released per fission $= 200 \text{ MeV}$,$1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$)

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