Turpentine oil is flowing through a tube of length $l$ and radius $r$. The pressure difference between the two ends of the tube is $P$. The viscosity of oil is given by $\eta = \frac{P(r^2 - x^2)}{4vl}$,where $v$ is the velocity of oil at a distance $x$ from the axis of the tube. The dimensions of $\eta$ are

  • A
    $[MLT^{-1}]$
  • B
    $[M^0L^0T^0]$
  • C
    $[ML^{-1}T^{-1}]$
  • D
    $[ML^2T^{-2}]$

Explore More

Similar Questions

The velocity of a particle depends upon time as $v = a + bt + ct^2$. If the velocity is in $m/s$,the unit of $a$ will be:

Write the dimensional formula for the intensity of radiation.

The physical quantity which has the same dimensional formula as that of $\frac{\text{Energy}}{\text{Mass} \times \text{Length}}$ is:

The dimensional formula of wave number is

The dimensions of surface tension are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo