Two batteries,one with an emf of 3,V and inte | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the current $I$ flow in the circuit in the anticlockwise direction.Applying Kirchhoff's Voltage Law $(KVL)$ to the entire loop:$15 + 3 = (1 +

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) Let the current $I$ flow in the circuit in the anticlockwise direction.Applying Kirchhoff's Voltage Law $(KVL)$ to the entire loop:$15 + 3 = (1 + 2 + R) I$$18 = (3 + R) I$$I = \frac{18}{3 + R}$Given that the potential difference between points $a$ and $b$ is zero $(V_{ab} = 0)$:Starting from $a$ to $b$ through the $3\,V$ battery:$V_a - 3 + I(1) = V_b$$V_a - V_b = 3 - I = 0$$I = 3\,A$Substituting the value of $I$ in the loop equation:$3 = \frac{18}{3 + R}$$3 + R = 6$$R = 3\,\Omega$

Similar Questions

The value of current in the $6 \,\Omega$ resistance is $....\,A$

In the circuit shown in the figure,$P \neq R$. The reading of the galvanometer remains the same with switch $S$ open or closed. Then

What are the uses of a Wheatstone bridge?

The electric current $i$ in the circuit shown is (in $\text{ A}$)

Find the value of the current through the $2\,\Omega$ resistance for the given circuit. (in $,A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module