Two bodies of masses m and 4m are moving with | vedclass

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(C) The relationship between linear momentum $(p)$,mass $(m)$,and kinetic energy $(K.E.)$ is given by the formula: $p = \sqrt{2m(K.E.)}$.Since the kin

Vedclass · Accepted Answer

$1:2$

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(C) The relationship between linear momentum $(p)$,mass $(m)$,and kinetic energy $(K.E.)$ is given by the formula: $p = \sqrt{2m(K.E.)}$.Since the kinetic energy $(K.E.)$ is equal for both bodies,we have $p \propto \sqrt{m}$.Therefore,the ratio of their linear momentums is $\frac{p_1}{p_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = m$ and $m_2 = 4m$,we substitute these values:$\frac{p_1}{p_2} = \sqrt{\frac{m}{4m}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Thus,the ratio is $1:2$.

Two bodies of masses $m$ and $4m$ are moving with equal kinetic energy $(K.E.)$. The ratio of their linear momentums is

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