Two bodies with kinetic energies in the ratio | vedclass

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(B) The kinetic energy $K$ of a body with linear momentum $p$ and mass $m$ is given by $K = \frac{p^2}{2m}$.Since the linear momentum $p$ is constant

Vedclass · Accepted Answer

$1:3$

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(B) The kinetic energy $K$ of a body with linear momentum $p$ and mass $m$ is given by $K = \frac{p^2}{2m}$.Since the linear momentum $p$ is constant for both bodies, we have $K \propto \frac{1}{m}$.Therefore, the ratio of masses is $\frac{m_1}{m_2} = \frac{K_2}{K_1}$.Given the ratio of kinetic energies $\frac{K_1}{K_2} = \frac{3}{1}$, we substitute this into the equation:$\frac{m_1}{m_2} = \frac{1}{3}$.Thus, the ratio of their masses is $1:3$.

Two bodies with kinetic energies in the ratio of $3:1$ are moving with equal linear momentum. The ratio of their masses is

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