Two bodies with masses M_1 and M_2 have equal | vedclass

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(D) The kinetic energy $K$ of a body of mass $m$ and momentum $p$ is given by the relation $K = \frac{p^2}{2m}$.Since the kinetic energies of the two

Vedclass · Accepted Answer

$\sqrt{M_1} : \sqrt{M_2}$

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(D) The kinetic energy $K$ of a body of mass $m$ and momentum $p$ is given by the relation $K = \frac{p^2}{2m}$.Since the kinetic energies of the two bodies are equal,we have $K_1 = K_2$.Therefore,$\frac{p_1^2}{2M_1} = \frac{p_2^2}{2M_2}$.Rearranging the terms,we get $\frac{p_1^2}{p_2^2} = \frac{M_1}{M_2}$.Taking the square root on both sides,we obtain $\frac{p_1}{p_2} = \sqrt{\frac{M_1}{M_2}} = \sqrt{M_1} : \sqrt{M_2}$.

Two bodies with masses $M_1$ and $M_2$ have equal kinetic energies. If $p_1$ and $p_2$ are their respective momenta,then $p_1/p_2$ is equal to

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