A body of mass 2 kg is projected vertically | vedclass

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(C) According to the law of conservation of energy,the speed of the body when it returns to the point of projection will be equal to the speed with wh

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$4$

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(C) According to the law of conservation of energy,the speed of the body when it returns to the point of projection will be equal to the speed with which it was projected.Since the body is projected upwards with a velocity $v = 2 \ m \ s^{-1}$,it will return to the ground with the same velocity $v = 2 \ m \ s^{-1}$.The kinetic energy $K$ is given by the formula $K = \frac{1}{2}mv^2$.Substituting the values $m = 2 \ kg$ and $v = 2 \ m \ s^{-1}$:$K = \frac{1}{2} 	imes 2 	imes (2)^2 = 4 \ J$.

$A$ body of mass $2 \ kg$ is projected vertically upwards with a velocity of $2 \ m \ s^{-1}$. What will be its kinetic energy in $J$ just before it hits the ground?

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