(B) The initial charges on the capacitors are $Q_1 = C_1 V_1 = 3 \mu F \times 12 V = 36 \mu C$ and $Q_2 = C_2 V_2 = 6 \mu F \times 12 V = 72 \mu C$.Si

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(B) The initial charges on the capacitors are $Q_1 = C_1 V_1 = 3 \mu F \times 12 V = 36 \mu C$ and $Q_2 = C_2 V_2 = 6 \mu F \times 12 V = 72 \mu C$.Since the positive plate of one is connected to the negative plate of the other,the net charge on the system is $Q_{net} = |Q_2 - Q_1| = |72 \mu C - 36 \mu C| = 36 \mu C$.The equivalent capacitance of the parallel combination is $C_{eq} = C_1 + C_2 = 3 \mu F + 6 \mu F = 9 \mu F$.The common potential difference across the capacitors is $V = \frac{Q_{net}}{C_{eq}} = \frac{36 \mu C}{9 \mu F} = 4 V$.

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

Medium

Two capacitors of capacitances $3 \mu F$ and $6 \mu F$ are charged to a potential of $12 V$ each. They are now connected to each other,with the positive plate of each joined to the negative plate of the other. The potential difference across each will be $volt$.

A
$6$
B
$4$
C
$3$
D
$0$

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

$A$ $600\,pF$ capacitor is charged by a $200\,V$ supply. It is then disconnected from the supply and connected to another uncharged $600\,pF$ capacitor. The electrostatic energy lost in the process is $.........\,\mu J$.

DifficultJEE MAIN 2023

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$A$ capacitor of capacitance $C$ and potential $V$ has energy $E$. It is connected to another capacitor of capacitance $2C$ and potential $2V$. Then the loss of energy is $\frac{x}{3} E$,where $x$ is . . . . . . .

DifficultJEE MAIN 2024

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Two conducting spheres of radii $R_1$ and $R_2$ are charged with charges $Q_1$ and $Q_2$ respectively. When they are brought into contact with each other:

Difficult

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An uncharged parallel plate capacitor having a dielectric of constant $K$ is connected to a similar air-cored parallel plate capacitor charged to a potential $V$. The two capacitors share charges and the common potential becomes $V^{\prime}$. The dielectric constant $K$ is

Medium

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Two spheres $A$ and $B$ of radius $4\,cm$ and $6\,cm$ are given charges of $80\,\mu C$ and $40\,\mu C$ respectively. If they are connected by a fine wire,the amount of charge flowing from one to the other is

Medium

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Two capacitors of capacitances $3 \mu F$ and $6 \mu F$ are charged to a potential of $12 V$ each. They are now connected to each other,with the positive plate of each joined to the negative plate of the other. The potential difference across each will be $volt$.

Similar Questions

$A$ $600\,pF$ capacitor is charged by a $200\,V$ supply. It is then disconnected from the supply and connected to another uncharged $600\,pF$ capacitor. The electrostatic energy lost in the process is $.........\,\mu J$.

$A$ capacitor of capacitance $C$ and potential $V$ has energy $E$. It is connected to another capacitor of capacitance $2C$ and potential $2V$. Then the loss of energy is $\frac{x}{3} E$,where $x$ is . . . . . . .

Two conducting spheres of radii $R_1$ and $R_2$ are charged with charges $Q_1$ and $Q_2$ respectively. When they are brought into contact with each other:

An uncharged parallel plate capacitor having a dielectric of constant $K$ is connected to a similar air-cored parallel plate capacitor charged to a potential $V$. The two capacitors share charges and the common potential becomes $V^{\prime}$. The dielectric constant $K$ is

Two spheres $A$ and $B$ of radius $4\,cm$ and $6\,cm$ are given charges of $80\,\mu C$ and $40\,\mu C$ respectively. If they are connected by a fine wire,the amount of charge flowing from one to the other is

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