Two liquids A and B have P_A^o and P_B^o in t | vedclass

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(A) Given: $P_A^o : P_B^o = 1 : 3$ and $n_A : n_B = 1 : 3$.Let $P_A^o = x$ and $P_B^o = 3x$.Mole fraction of $A$ in liquid phase $(x_A)$ = $\frac{1}{1

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$0.1$

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(A) Given: $P_A^o : P_B^o = 1 : 3$ and $n_A : n_B = 1 : 3$.Let $P_A^o = x$ and $P_B^o = 3x$.Mole fraction of $A$ in liquid phase $(x_A)$ = $\frac{1}{1+3} = 0.25$.Mole fraction of $B$ in liquid phase $(x_B)$ = $\frac{3}{1+3} = 0.75$.Partial pressure of $A$ $(P_A)$ = $x_A 	imes P_A^o = 0.25 	imes x = 0.25x$.Partial pressure of $B$ $(P_B)$ = $x_B 	imes P_B^o = 0.75 	imes 3x = 2.25x$.Total pressure $(P_T)$ = $P_A + P_B = 0.25x + 2.25x = 2.5x$.Mole fraction of $A$ in vapour phase $(y_A)$ = $\frac{P_A}{P_T} = \frac{0.25x}{2.5x} = 0.1$.

Two liquids $A$ and $B$ have $P_A^o$ and $P_B^o$ in the ratio of $1 : 3$ and the ratio of number of moles of $A$ and $B$ in the liquid phase are $1 : 3$. The mole fraction of $A$ in the vapour phase in equilibrium with the solution is equal to:

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