Two particles, A and B, having equal charges, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The radius $R$ of the circular path followed by a charged particle in a magnetic field is given by $R = \frac{mv}{qB} = \frac{\sqrt{2mK}}{qB}$, wh

Vedclass · Accepted Answer

$(R_{1} / R_{2})^{2}$

Vedclass · Answer

(B) The radius $R$ of the circular path followed by a charged particle in a magnetic field is given by $R = \frac{mv}{qB} = \frac{\sqrt{2mK}}{qB}$, where $K$ is the kinetic energy.Since the particle is accelerated through a potential difference $V$, its kinetic energy is $K = qV$.Substituting this into the radius formula, we get $R = \frac{\sqrt{2mqV}}{qB} = \frac{1}{B} \sqrt{\frac{2mV}{q}}$.Given that $q$, $V$, and $B$ are the same for both particles, we have $R \propto \sqrt{m}$.Therefore, $\frac{R_{1}}{R_{2}} = \sqrt{\frac{m_{A}}{m_{B}}}$.Squaring both sides, we get $\frac{m_{A}}{m_{B}} = \left(\frac{R_{1}}{R_{2}}\right)^{2}$.

Two particles, $A$ and $B$, having equal charges, after being accelerated through the same potential difference, enter into a region of uniform magnetic field and the particles describe circular paths of radii $R_{1}$ and $R_{2}$ respectively. The ratio of the masses of $A$ and $B$ is

Similar Questions

When a charged particle moving with velocity $\vec{V}$ is subjected to a magnetic field of induction $\vec{B}$,the force on it is non-zero. This implies that the:

Two identical charged particles enter a uniform magnetic field with the same speed but at angles $30^{\circ}$ and $60^{\circ}$ with the field. Let $a, b,$ and $c$ be the ratios of their time periods,radii,and pitches of the helical paths,respectively. Then:

$A$ particle of mass $0.6\, g$ and having a charge of $25\, nC$ is moving horizontally with a uniform velocity $1.2 \times 10^4\, m/s$ in a uniform magnetic field. If the particle continues to move with uniform velocity,the value of the magnetic induction is $(g = 10\, m/s^2)$.

$A$ charge $Q$ is moving through a distance $d\vec{l}$ in a magnetic field $\vec{B}$. Find the value of the work done by the magnetic field.

Vedclass Test Series

Exam Paper Generator

Online Exam Module