Two persons $A$ and $B$ are throwing an unbiased six-faced dice alternatively,with the condition that the person who throws $3$ first wins the game. If $A$ starts the game,then the probabilities of $A$ and $B$ winning the game are,respectively:

  • A
    $\frac{6}{11}, \frac{5}{11}$
  • B
    $\frac{5}{11}, \frac{6}{11}$
  • C
    $\frac{8}{11}, \frac{3}{11}$
  • D
    $\frac{3}{11}, \frac{8}{11}$

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