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(D) The fringe width $\beta$ in a Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelen

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(D) The fringe width $\beta$ in a Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the screen and the sources,and $d$ is the distance between the two sources.From this formula,we can see that the fringe width is directly proportional to the distance $D$,i.e.,$\beta \propto D$.Given that the initial fringe width is $\beta_1 = 2w$ at distance $D_1 = D$.If the distance is doubled,$D_2 = 2D$.Then the new fringe width $\beta_2$ will be: $\beta_2 = \beta_1 	imes \frac{D_2}{D_1} = 2w 	imes \frac{2D}{D} = 4w$.Therefore,the fringe width becomes $4w$.

Two sources produce an interference pattern which is observed on a screen,at a distance $D$ from the sources. The fringe width is $2w$. If the distance $D$ is now doubled,the fringe width will be:

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