The unknown product (A) in the following reac | vedclass

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(A) The reaction of salicylic acid $(2-hydroxybenzoic \ acid)$ with $I-Cl$ is an electrophilic aromatic substitution reaction.The $-OH$ group is a str

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$3,5-$diiodosalicylic acid

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(A) The reaction of salicylic acid $(2-hydroxybenzoic \ acid)$ with $I-Cl$ is an electrophilic aromatic substitution reaction.The $-OH$ group is a strong activating group and is ortho/para directing.The $-COOH$ group is a deactivating group and is meta directing.In salicylic acid,the $-OH$ group directs the incoming electrophile $(I^+)$ to the ortho and para positions relative to itself.The positions ortho and para to the $-OH$ group are the $3$ and $5$ positions of the benzene ring.Therefore,the electrophilic iodination occurs at the $3$ and $5$ positions,resulting in $3,5-diiodosalicylic \ acid$.

The unknown product $(A)$ in the following reaction is:
Salicylic acid + $2I-Cl \rightarrow (A)$

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The unknown product $(A)$ in the following reaction is:Salicylic acid + $2I-Cl \rightarrow (A)$