Verify whether the following is True or False:
$-3$ is a zero of $y^{2}+y-6$.
$-3$ is a zero of $y^{2}+y-6$.
(TRUE) zero of a polynomial $p(y)$ is a value $c$ such that $p(c) = 0$.
Let $p(y) = y^{2} + y - 6$.
Substitute $y = -3$ into the polynomial:
$p(-3) = (-3)^{2} + (-3) - 6$
$p(-3) = 9 - 3 - 6$
$p(-3) = 0$.
Since $p(-3) = 0$,it is True that $-3$ is a zero of the polynomial $y^{2} + y - 6$.
Let $p(y) = y^{2} + y - 6$.
Substitute $y = -3$ into the polynomial:
$p(-3) = (-3)^{2} + (-3) - 6$
$p(-3) = 9 - 3 - 6$
$p(-3) = 0$.
Since $p(-3) = 0$,it is True that $-3$ is a zero of the polynomial $y^{2} + y - 6$.
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