Verify whether the following is a zero of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To verify if $x = \frac{4}{5}$ is a zero of the polynomial $p(x) = 5x - \pi$,we substitute $x = \frac{4}{5}$ into the polynomial.$p\left(\frac{4}{

Vedclass · Accepted Answer

No,it is not a zero.

Vedclass · Answer

(B) To verify if $x = \frac{4}{5}$ is a zero of the polynomial $p(x) = 5x - \pi$,we substitute $x = \frac{4}{5}$ into the polynomial.$p\left(\frac{4}{5}ight) = 5\left(\frac{4}{5}ight) - \pi$$p\left(\frac{4}{5}ight) = 4 - \pi$Since $4 - \pi 
eq 0$,the value of the polynomial at $x = \frac{4}{5}$ is not zero.Therefore,$x = \frac{4}{5}$ is not a zero of the given polynomial $p(x) = 5x - \pi$.

Verify whether the following is a zero of the polynomial indicated against it:
$p(x) = 5x - \pi, \, x = \frac{4}{5}$

Similar Questions

Determine which of the following polynomials has $(x + 1)$ as a factor: $x^{4} + 3x^{3} + 3x^{2} + x + 1$.

Check whether $7+3x$ is a factor of $3x^3+7x$.

Factorise $x^{3}-23 x^{2}+142 x-120$

Find the value of $k$, if $x - 1$ is a factor of $p(x)$ in this case: $p(x) = kx^2 - \sqrt{2}x + 1$.

Write the degree of each of the following polynomials:
$(i)$ $5t - \sqrt{7}$
$(ii)$ $3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Verify whether the following is a zero of the polynomial indicated against it:$p(x) = 5x - \pi, \, x = \frac{4}{5}$