What are A, B and C in the following reaction | vedclass

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(A) The reaction of phthalic acid with ammonia proceeds as follows:
$1$. Phthalic acid reacts with $2$ moles of $NH_3$ to form ammonium phthalate $(A

Vedclass · Accepted Answer

$A$: Ammonium phthalate,$B$: Phthalamide,$C$: Phthalimide

Vedclass · Answer

(A) The reaction of phthalic acid with ammonia proceeds as follows:
$1$. Phthalic acid reacts with $2$ moles of $NH_3$ to form ammonium phthalate $(A)$: $C_6H_4(COOH)_2 + 2NH_3 \longrightarrow C_6H_4(COO^-NH_4^+)_2$.
$2$. Heating ammonium phthalate $(A)$ results in the loss of water to form phthalamide $(B)$: $C_6H_4(COO^-NH_4^+)_2 \stackrel{\Delta}{\longrightarrow} C_6H_4(CONH_2)_2 + 2H_2O$.
$3$. Further heating of phthalamide $(B)$ at high temperature leads to the loss of $NH_3$ to form phthalimide $(C)$: $C_6H_4(CONH_2)_2 \stackrel{	ext{High temperature}}{\longrightarrow} C_6H_4(CO)_2NH + NH_3$.

Column-$I$ (formula)	Column-$II$ (name)
$A$. $RCH=NH$	$i$. Diisobutyl aluminium hydride
$B$. $AlH(i-Bu)_2$	$ii$. Benzalchloride
$C$. $C_6H_5-CH(OCOCH_3)_2$	$iii$. Imine
$D$. $C_6H_5CHCl_2$	$iv$. Benzylidene diacetate

What are $A, B$ and $C$ in the following reactions?
Phthalic acid $+\, NH_3 \rightarrow A \xrightarrow{\Delta} B \xrightarrow{\text{High temperature}} C$

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Match the formulas in Column-$I$ with their names in Column-$II$.

Column-$I$ (formula) Column-$II$ (name)

$A$. $RCH=NH$ $i$. Diisobutyl aluminium hydride

$B$. $AlH(i-Bu)_2$ $ii$. Benzalchloride

$C$. $C_6H_5-CH(OCOCH_3)_2$ $iii$. Imine

$D$. $C_6H_5CHCl_2$ $iv$. Benzylidene diacetate

In the following reaction,$X$ and $Y$ are respectively
$CH_3 COOH + NH_3$ $\longrightarrow X \stackrel{\Delta}{}$ ${\longrightarrow} Y + H_2 O$

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What are $A, B$ and $C$ in the following reactions? Phthalic acid $+\, NH_3 \rightarrow A \xrightarrow{\Delta} B \xrightarrow{\text{High temperature}} C$