What is the volume occupied by 1 molecule of | vedclass

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(B) The molar mass of water $(H_2O)$ is $18 \,g/mol$.$1 \,mol$ of water contains $6.022 	imes 10^{23}$ molecules.Mass of $6.022 	imes 10^{23}$ molec

Vedclass · Accepted Answer

$2.98 	imes 10^{-23} \,cm^3$

Vedclass · Answer

(B) The molar mass of water $(H_2O)$ is $18 \,g/mol$.$1 \,mol$ of water contains $6.022 	imes 10^{23}$ molecules.Mass of $6.022 	imes 10^{23}$ molecules of water $= 18 \,g$.Therefore, the mass of $1$ molecule of water $= \frac{18 \,g}{6.022 	imes 10^{23}} = 2.988 	imes 10^{-23} \,g$.Given that $	ext{density} = \frac{	ext{mass}}{	ext{volume}}$, the volume occupied by $1$ molecule is $	ext{Volume} = \frac{	ext{mass}}{	ext{density}}$.$	ext{Volume} = \frac{2.988 	imes 10^{-23} \,g}{1 \,g \,cm^{-3}} = 2.988 	imes 10^{-23} \,cm^3 \approx 2.98 	imes 10^{-23} \,cm^3$.

What is the volume occupied by $1$ molecule of water, if its density is $1 \,g \,cm^{-3}$?

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