What is the least value that should be added | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the number that is divisible by $7, 11,$ and $14$,we first need to find their Least Common Multiple $(LCM)$.Step $1$: Find $\operatorname{

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(B) To find the number that is divisible by $7, 11,$ and $14$,we first need to find their Least Common Multiple $(LCM)$.Step $1$: Find $\operatorname{LCM}(7, 11, 14)$.$7 = 7 	imes 1$$11 = 11 	imes 1$$14 = 2 	imes 7$$\operatorname{LCM} = 2 	imes 7 	imes 11 = 154$.Step $2$: Divide $1812$ by $154$ to find the remainder.$1812 \div 154 = 11$ with a remainder.$154 	imes 11 = 1694$.$1812 - 1694 = 118$.So,the remainder is $118$.Step $3$: Calculate the value to be added.To make $1812$ divisible by $154$,we need to add the difference between the divisor $(154)$ and the remainder $(118)$.Value to be added $= 154 - 118 = 36$.

What is the least value that should be added to $1812$ to make it divisible by $7, 11,$ and $14$?

Similar Questions

Find the least number of five digits which when divided by $8, 12, 16$ and $20$ leaves remainders $1, 5, 9$ and $13$ respectively.

The traffic lights at three different road crossings change after $24$ seconds,$36$ seconds,and $54$ seconds,respectively. If they all change simultaneously at $10:15:00$ am,then at what time will they again change simultaneously?

What is the $H.C.F.$ of $\frac{4}{9}, \frac{10}{21}$ and $\frac{20}{63}$?

Find the greatest number of four digits which is exactly divisible by $24, 28, 30$ and $35$.

The product of two $2$-digit numbers is $2160$ and their $H.C.F.$ is $12$. The numbers are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module