The traffic lights at three different road cr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find when the traffic lights will change simultaneously again,we need to calculate the Least Common Multiple $(LCM)$ of the time intervals: $24

Vedclass · Accepted Answer

$10:18:36$ am

Vedclass · Answer

(B) To find when the traffic lights will change simultaneously again,we need to calculate the Least Common Multiple $(LCM)$ of the time intervals: $24$,$36$,and $54$ seconds.Prime factorization:$24 = 2^3 	imes 3^1$$36 = 2^2 	imes 3^2$$54 = 2^1 	imes 3^3$$LCM = 2^3 	imes 3^3 = 8 	imes 27 = 216$ seconds.Convert $216$ seconds into minutes:$216 \div 60 = 3$ minutes and $36$ seconds.Adding this duration to the initial time of $10:15:00$ am:$10:15:00 + 0:03:36 = 10:18:36$ am.Therefore,the traffic lights will again change simultaneously at $10:18:36$ am.

The traffic lights at three different road crossings change after $24$ seconds,$36$ seconds,and $54$ seconds,respectively. If they all change simultaneously at $10:15:00$ am,then at what time will they again change simultaneously?

Similar Questions

Two pipes of length $1.5\, m$ and $1.2\, m$ are to be cut into equal pieces without leaving any extra length of pipes. The greatest length of the pipe pieces of same size which can be cut from these two lengths will be (in $metre$)

Find the least common multiple of $24, 36,$ and $40.$

$L.C.M.$ and $H.C.F.$ of two numbers $x$ and $y$ are $315$ and $3,$ respectively. If $x+y=36,$ the value of $\frac{1}{x}+\frac{1}{y}$ is

The number of prime factors in the expression $(6)^{10} \times (7)^{17} \times (11)^{27}$ is

There are five bells which start ringing together at intervals of $3, 6, 9, 12$ and $15$ seconds respectively. In $36$ minutes,how many times will the bells ring simultaneously?

Vedclass Test Series

Exam Paper Generator

Online Exam Module